OgreMkV
Posts: 3668
Joined: Oct. 2009
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| Quote (Jerry Don Bauer @ Nov. 19 2012,16:37) | | Quote (OgreMkV @ Nov. 19 2012,16:03) | Interesting that the part you didn't do was in a previous comment.
Do you want to calculate or measure the CSI of an organism or teach me to do so and us compare the results? |
You seem so ignorant in this subject (don't mean that as a slur just an observation as we are all ignorant in some subjects).
Why on earth would you want to calculate the CSI of an organism? Just a simple genome is lightyears over the 500 measly bits of information that make something CSI. Many proteins are as well...common sense should tell you that.
Look at the amount of information in the human genome:
| Quote | The human genome contains the complete genetic information of the organism as DNA sequences stored in 23 chromosomes (22 autosomal chromosomes and one X or Y sex chromosome), structures that are organized from DNA and protein. A DNA molecule consists of two strands that form the iconic double-helix “twisted ladder”, whose backbone, which made of sugar and phosphate molecules, is connected by rungs of nitrogen-containing bases. DNA is composed of 4 different bases: Adenine (A), Thymine (T), Cytosine ©, and Guanine (G). These bases are always paired in such a way that Adenine connects to Thymine, and Cytosine connects to Guanine. These pairings produce 4 different base pair possibilities: A-T, T-A, G-C, and C-G. The haploid human genome (containing only 1 copy of each chromosome) consists of roughly 3 billion of these base pairs grouped into 23 chromosomes. A human being inherits two sets of genomes (one from each parent), and thus two sets of chromosomes, for a total of 46 chromosomes, representing the diploid genome, which contains about 6×10^9 base pairs.
Comparing the genome to computer data storage
In order to represent a DNA sequence on a computer, we need to be able to represent all 4 base pair possibilities in a binary format (0 and 1). These 0 and 1 bits are usually grouped together to form a larger unit, with the smallest being a “byte” that represents 8 bits. We can denote each base pair using a minimum of 2 bits, which yields 4 different bit combinations (00, 01, 10, and 11). Each 2-bit combination would represent one DNA base pair. A single byte (or 8 bits) can represent 4 DNA base pairs. In order to represent the entire diploid human genome in terms of bytes, we can perform the following calculations:
6×10^9 base pairs/diploid genome x 1 byte/4 base pairs = 1.5×10^9 bytes or 1.5 Gigabytes, about 2 CDs worth of space! |
http://bitesizebio.com/article....-genome
is 1.5 Gigabytes more than 500 bits? Then why would we want to go any further than this as you already have the answer before you start.
ANY organism will be over 500 bits. |
OK. If I am ignorant on the subject, it's because every creationist I've ever talked to has been utterly unable to explain or teach the concept.
Since any organism is over 500 bits... let's try this.
5093413647
5962916509
4066005562
8540770698
8342922442
0194220209
7331543188
7173101712
5811761471
3261216342
2525310538
4613627960
9767559584
8786679179
7022618236
5134707276
1505272783
6020313600
8013081724
2444671310
5268821392
0881048845
1181910939
0754282725
9802869949
3733118584
7969279971
8150134026
7987778049
5178595812
2668421641
8163467125
0645780953
5684243267
1401437548
9391680033
7856973231
7145812146
8632651141
7699167635
0557559516
8611985974
7805273622
9849541633
3279510329
7149754142
7096458973
6301485923
1880042518
4930165865
Is this CSI? Yes/No Why?
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Ignored by those who can't provide evidence for their claims.
http://skepticink.com/smilodo....retreat
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