Robin
Posts: 1431 Joined: Sep. 2009

Got a statistics problem for anyone feeling bored:
(1+mi)*(1+mi+1)*(1+mi+2)*...(1+mn)=(1+X)^n
Suppose each value of M has a standard deviation associated with it. What is the standard deviation of X? Is it a simpler calculation if the standard deviation of each M is the same?
This is from my wife's friend. It's been over 25 years since I've done statistics so I'm rusty and trying to brush up. Any help would be appreciated.
Oh...and the notation is the way it is because I've not figured out how to get series fonts to work.
 we IDists rule in design for the flagellum and cilium largely because they do look designed. Bilbo
The only reason you reject Thor is because, like a cushion, you bear the imprint of the biggest arse that sat on you. Louis
